foo = fail
bar(foo) = <foo> [ ]

is analyzed as:
foo{1} = fail
bar(foo{2}) = <foo{1}> [ ]

Submitted by Maartje on 10 June 2011 at 00:54

On 14 June 2011 at 12:49 Lennart Kats tagged stratego

On 21 July 2011 at 21:31 Maartje closed this issue.

On 22 July 2011 at 11:27 Maartje commented:

solved.

Log in to post comments